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(3a^2/2)=1/2-a
We move all terms to the left:
(3a^2/2)-(1/2-a)=0
Domain of the equation: 2-a)!=0We add all the numbers together, and all the variables
We move all terms containing a to the left, all other terms to the right
-a)!=-2
a!=-2/1
a!=-2
a∈R
(3a^2/2)-(-1a+1/2)=0
We get rid of parentheses
3a^2/2+1a-1/2=0
We multiply all the terms by the denominator
3a^2+1a*2-1=0
Wy multiply elements
3a^2+2a-1=0
a = 3; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·3·(-1)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*3}=\frac{-6}{6} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*3}=\frac{2}{6} =1/3 $
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